Basic Calculations for a Power Plant- Calculating the Coal Quantity

Written by:  • Edited by: Lamar Stonecypher
Published Oct 15, 2009
• Related Guides: Electricity

How to make quick estimate of the coal required for running a power plant? This article describes a simple method.

Very often, the Power engineer is required to perform some basic calculations regarding the key parameters of a power plant. Most important is the quantity and cost of fuel that is required.This article gives the simple calculation method. (A detailed calculation required in the context of a contract, tender, performance repor,t or a legal document may require more accurate input data.)

We take the example of a 100 MW Coal Fired Power Plant.

Energy Content in Coal

The basic function of the power plant is to convert energy in coal to electricity. Therefore, the first thing we should know is how much energy there is in coal. Energy content of coal is given in terms of KiloJoules (kJ) per Kilogram (kg) of coal as the Gross calorific value (GCV) or the Higher Heating value (HHV) of coal. This value can vary from 10500 kJ/kg to 25000 kJ/kg depending on the quality and type of the coal.

You should have an idea of the type of coal, or the source or mine from where the the plant gets the coal. Published data about the sources, mines, regions or the procurement data gives an idea about the HHV of coal. For this example we use a HHV of 20,000 kJ/kg.

Efficiency

Energy conversion takes place in two stages.

  • The first part of the conversion is efficiency of the boiler and combustion. For this example we take 88 % on an HHV basis that is the normal range for a well-optimized power plant.
  • Second part is the steam cycle efficiency. Modern Rankine cycle, adopted in coal fired power plants, have efficiencies that vary from 32 % to 42 %. This depends mainly on the steam parameters. Higher steam perssure and temperatures in the range of 600 ° C and 230 bar have efficiencies around 42 %. We assume a value of 38 % for our case.

Heat Rate

Heat rate is the heat input required to produce one unit of electricity. (1 kw hr)

  • One Kw is 3600 kJ/hr. If the energy conversion is 100 % efficient then to produce one unit of electricity we require 3600 kJ.
  • After considering the conversion efficiency in a power plant we require an heat input of (3600 / 33.44% ) 10765 kJ/ kw hr.

Coal Quantity

  • Since coal has a heat value of 20,000 kJ/kg, for producing one kw.hr we require (10765 / 20000) 0.538 kg of coal. This translates to (0.538 x 100 x 1,000) 53800 kg/hr (53.8 T/hr) of coal for an output of 100 MW.

Coal Cost

Basic cost of coal depends on the market conditions. Transportation costs, regional influences and government taxes are also part of the cost. Coal trader’s web sites give base prices in the international market.

  • We take a coal price of around 65 $ / Ton.
  • The cost of coal consumed by 100 MW power plant is (53.8 x 65) 3497 $ /hr
  • A 100 MW unit produces 100,000 units of electricity. So the cost of coal per unit of electricity is (3497/100,000) 3.5 cents per unit.


Comments

Showing all 22 comments
 
DEEPAKSIVAM Jan 4, 2012 9:10 AM
RE: Basic Calculations for a Power Plant- Calculating the Coal Quantity
Please explain me how did you calculated 88% on HHv?<br>88% of HHV &amp; Boiler efficiency both are same?<br>
abhi Sep 19, 2011 12:44 PM
GVC
will there be any difference in calculation with GCV value?
yv chalapathirao Jul 26, 2011 1:34 AM
wate and steam calculation
plese let me know balance of water and steam calculations
yv chalapathirao Jul 26, 2011 1:33 AM
water and steam calculation
I am working in DM Plant and power plant, I would like to get more details on power plant water chemistry.
johnzactruba Mar 2, 2011 9:58 AM
reply Firson
You have to split calculation into two sections.
1. The steam side efficiency can be found out by input - steam flow and enthalpy input into turbine and output the electrical energy. Of course one has to account for other inputs and outputs like FW to boiler , condenser cooling water in and out. This gives the steam side heat rate.
2. Boiler efficiency by the indirect method. Since you use multiple fuels, the easiest way is to find the weighted average Calorific value and constituent analysis. Use this to find the various losses on per kg basis to get the boiler efficiency %.
3. Steam plant heat rate divided by boiler eficiency gives you the Plant heat rate.
Firson Mar 2, 2011 4:20 AM
How to calculate Power Plant Efficiency with fuel combination?
Dear sir,
How to calculate total efficiency of power plant by using fuel combination (palm kernel shell,bark, dust, coal) with power plant performance data:
1.Power plant (gross power output=15 MW, Auxiliary power consumption-approx = 12%, 100% Net Plant Heat Rate = 4571 kcal/kwh)
2.Boiler (Rated output = 2x40 ton/hour, Efficiency = 81%)
3.Turbine generator (Rated output = 15 MW)
Thank you for your answer.
johnzactruba Feb 5, 2011 8:20 PM
reply Kaisin
The basic method is the same as in the article. Instead of coal and its CV
CV of gas in the appropriate units have to be used.
Kaisin Feb 3, 2011 9:41 PM
Basic Calculations for a Power Plant- Calculating the Fuel gas Quantity
I would like to know how to Basic Calculations for a Power Plant- Calculating the Fuel gas Quantity like MMBTU,SCF
vinoth Jan 20, 2011 2:31 PM
RE: Basic Calculations for a Power Plant- Calculating the Coal Quantity
difference between cogeneration and captive power plant. list out various points ( give in detail)
H.Nataraj Dec 17, 2010 10:53 AM
materials balance calculation and water consumption
We need specific consumption of coal and dolochar for 20MW captive power plant with Air cooled condenser system
syed fawad ali shah May 18, 2010 1:58 AM
question
12-15 tons/hr steam is generated at 200c and 16kg/cm2 pressure in the boiler steam generation arrangement .calculate the amount of coal required by the furnace.
please send answer on my mail
Dube Vuyiswa Mar 30, 2010 4:26 AM
coal input through a 3 pass fire tube boiler
Hi there
M a graduate trainee in chemical engineering,have a challenge to determine coal input,consumptiom through the coal fire tube boiler. want to quantify amount of coal used.
johnzactruba Jan 27, 2010 6:05 PM
reply anugia
Coal contains moisture and hydrogen. Hydrogen on combustion becomes moisture. This moisture evaporates during combustion taking the latent heat from the heat released by the combustion mainly from Carbon and Hydrogen. This heat is not available for heat transfer . So some people report coal heating values as HHV -the total heat of combustion. Others report this as LHV after reducing the heat lost to evaporate moisture.
Plant heat rates are denoted both on HHV or LHV basis, but this will be mentioned there. In gaseous fuels, because of high nhydrogen content Heat rate is denoted as on LHV basis.
The final calculation of fuel quantity will not be effected because , the boiler efficiency also is calculated on the same basis either HHV or LHV. As long as you take the same basis all along both methods will give the same results.
anugia@yahoo.com Jan 25, 2010 9:39 PM
what is the difference between hhv coal and lhv coal
what is the difference between hhv and lhv of coal on determining power plant heat rate?why should we use hhv instead of lhv?there's some contractor that use hhv or lhv to determine the heat rate...
you know if we use lhv,the heat rate must be lowered compare to if we use hhv..
but if i read the definitions,hhv is heat liberated when the vapor is condensed...
can u explain to me..
do you have literature about that
regards
anugia
johnzactruba Jan 14, 2010 5:19 PM
reply AKS
If Turbine heat rate is is 25i5 kcal/kwhr, then input to boiler is 2515/83% = 3030 kcal /Kwhr.
Since HHV is 2800 kcal/Kg
coal requirement is 3030/2800 = 1.08 kg/kwhr
AKS Jan 14, 2010 4:57 AM
Coal Consumption Rate
Friends, help me out with this:
Boiler Thermal Efficiency: 83% (for 100% coal having GCV of 2800 Kcal/Kg).
Turbine Heat rate at 100% TMCR : 2515 Kcal/kWhr.
how do you arrive at coal consumption rate?
K V RAO Dec 24, 2009 2:20 PM
steam turbine rotor metallurgy
i want to know all types of turbine rotor metallurgy used in manufacturing for thermal power plant
johnzactruba Dec 23, 2009 3:16 AM
reply ananth
BOP is Balance of Plant , this the collective name given to plant items other than Boiler , turbine generator and the water steam cycle systems.
EBOP is Electrical Balance oF plant other then the generator Transformer and the switch yard.
Captive power plant meets the electrical need for a specific industrial plant and does not feed to the grid.
Many industrial plants require steam for the process, co generation plants produce steam at the same time excess capacity is used to generate electricity to the grid.
K.ANANTH Dec 23, 2009 12:53 AM
boiler
difference between cogenaration and captive power plant. list out various points ( give in detail)
K.ANANTH Dec 23, 2009 12:51 AM
boiler
difference between boiler auxileries and accessories. what is BOP,EBOP etc how we can separate power plant equipments/parts
ummed singh bhati Nov 16, 2009 9:05 AM
All types of calculation of Thermal power plant
How did we can calculate the caol rate on the basis of coal GCV
b.b.rao Oct 19, 2009 11:41 AM
calculation of coal per unit power produced
the calculation more or less very reasonable and a good guide for practical calculations
 
blog comments powered by Disqus
Email to a friend