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Referring the figure, we see a flat surface whose moment of inertia is needed to be calculated about its X-X and Y-Y axis.
The area is divided into a number of narrow strips and one of the lengths is considered for the calculations.
Let,
dA = The area of the above strip
x = Distance of the center of gravity of the strip over the X-X axis and,
y = Distance of the center of gravity of the strip over the Y-Y axis.
Now, the moment of inertia as discussed in the previous section for the above strip about the Y-Y axis is = dA × x2.
To find the moment of inertia of the entire section, we integrate the above expression and get,
Iyy = ΣdAx2, Ixx = ΣdAy2 and Izz = ΣdAz2
Calculating Moment of Inertia of a Uniform Thin Rod
Two conditions may be considered with this:

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Moment of Inertia about the central axis, at right angles to the length of the rod:
Looking at the figure, consider the rod AB with O as its mid point and length 2l.
Let the total mass of the rod be equal to M and m the mass per unit length of the rod.
We discussed regarding the expression of moment of inertia in the first section, applying it to a small section dx of the rod, at a distance x from the mid point O, we have it as = Mass × x2 = (m.dx)x2 dx
For calculating the moment of inertia of the entire rod, we integrate the above expression across the whole length, i.e. through -l to +l,
Therefore Iyy = ʃmx2dx = m[x3/3] = 2/3ml3,
Since the total mass of the rod is shown as M, replacing 2ml by M, we get,
Ixy = Ml2/3

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Moment of inertia about the end of the rod, and at right angles to its length.
Referring to the figure we see a rod AB having a length 2l with m as its mass per unit length.
From the above discussions we know that for the shown small section dx of the rod, which is at a distance x from A, about Y-Y axis, its moment of inertia can be written as = Mass × x2 = mdx × x2 = mx2.dx
As done for the previous expressions, the moment of inertia of the whole rod is measured through integration of the above equation across 0 and 2l.
Therefore, Iyy = ʃ mx2.dx = m[x3/3] = m(8l3/3).
Because, the total mass of the rod is equal to M, we can write the above equation as,
Iyy = 4Ml2/3
Units of Moment of Inertia
The units of moment of inertia of a body may be identified from the units of its mass or area or length, we learn them below:
- The moment of inertia of a body may be expressed in kg.m2, if its mass and distance are in kg and meters respectively.
- The moment of inertia of an area of a body may be expressed in m4, if its area and distance are in square meters and meters respectively.
- In case the area is in square centimeters and the distance is in centimeters, the moment of inertia must be given in cm4.